document.write( "Question 424256: Show all work. A disc jockey has 7 songs to play. Three are slow songs, and four are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 7 songs if
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document.write( "• The songs can be played in any order.
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document.write( "• The first song must be a slow song and the last song must be a slow song.
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document.write( "• The first two songs must be fast songs.
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Algebra.Com's Answer #295814 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 7 songs to play. \n" ); document.write( "Three are slow songs, and \n" ); document.write( "four are fast songs. \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "Each song is to be played only once. \n" ); document.write( "In how many ways can the disc jockey play the 7 songs if \n" ); document.write( "• The songs can be played in any order:::7! = 5040 ways \n" ); document.write( "------------------------------------------------------------------- \n" ); document.write( "• The first song must be a slow song and the last song must be a slow song. \n" ); document.write( "1st song: 3 ways \n" ); document.write( "last song: 2 ways \n" ); document.write( "Middle 5 songs: 5! = 120 ways \n" ); document.write( "Total ways: 3*2*120 720 ways \n" ); document.write( "------------------------------------ \n" ); document.write( "• The first two songs must be fast songs. \n" ); document.write( "1st song: 4 ways \n" ); document.write( "2nd song: 3 ways \n" ); document.write( "last 5 songs: 5! = 120 \n" ); document.write( "Total ways:4*3*120 = 1440 ways \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |