document.write( "Question 424162: If 1 gallon of anti-freeze is 80% and 60 gallon is 25%, how many gallon of the 80% do you mix with the 25% to equal 70%? \n" ); document.write( "

Algebra.Com's Answer #295782 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x represent the number of gallon of the 80% needed
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document.write( "    Mixing to make the 70% solution
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document.write( " .80x + .25*60gal = .70(60gal+x)
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document.write( "        .10x = .45*60gal
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document.write( "           x = 270 gal
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document.write( "CHECKING our Answer***
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document.write( "  .80*270 + .25*60 = .70(330) = 231 \n" );
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