document.write( "Question 424134: Stuck on this one!\r
\n" ); document.write( "\n" ); document.write( "I select a number from the 12 numbers 1 through 12. Each number is equally likely to be chosen. Let A be the event: I chose an even number. Let B be the event: I chose a number less than or equal to 5.\r
\n" ); document.write( "\n" ); document.write( "Find each based on one selection from the 12 numbers.\r
\n" ); document.write( "\n" ); document.write( "a) P(A occurred or B occurred)
\n" ); document.write( "b) P(A occurred and B occurred)
\n" ); document.write( "c) P(A occurred given that B occurred\r
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\n" ); document.write( "\n" ); document.write( "I think c is P(A|B)=2/5 but not sure the rest.
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Algebra.Com's Answer #295773 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi\r
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document.write( "I select a number from the 12 numbers 1 through 12. Each number is equally likely to be chosen.
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document.write( "Let A be the event: I chose an even number: 6 even numbers from 1 to 12
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document.write( " Let B be the event: I chose a number less than or equal to 5. {5,4,3,2,1} 
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document.write( "a) P(A occurred or B occurred)= 6/12 + 5/12 - 2/12 = 9/12
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document.write( "b) P(A occurred and B occurred)= 2/12
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document.write( "c) P(A occurred given that B occurred) = 2/5 \r
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