document.write( "Question 424085: Height and Weight Suppose that the weight of a
\n" ); document.write( "person is directly proportional to the cube of the
\n" ); document.write( "person’s height. If one person weighs twice as much
\n" ); document.write( "as a (similarly proportioned) second person, by what
\n" ); document.write( "factor is the heavier person’s height greater than the
\n" ); document.write( "shorter person’s height?
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Algebra.Com's Answer #295725 by stanbon(75887)\"\" \"About 
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Height and Weight
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\n" ); document.write( "Suppose that the weight of a
\n" ); document.write( "person is directly proportional to the cube of the
\n" ); document.write( "person’s height.
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\n" ); document.write( "W = k*H^3
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\n" ); document.write( "If one person weighs twice as much
\n" ); document.write( "as a (similarly proportioned) second person, by what
\n" ); document.write( "factor is the heavier person’s height greater than the
\n" ); document.write( "shorter person’s height?
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\n" ); document.write( "Let the 2nd person's weight be \"x\"
\n" ); document.write( "x = k*H^3
\n" ); document.write( "H = [x/k]^(1/3) (2nd person's height)
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\n" ); document.write( "\n" ); document.write( "The 1st person's weight is \"2x\"
\n" ); document.write( "2x = kH^3
\n" ); document.write( "H = [2x/k]^(1/3)
\n" ); document.write( "H = 2^(1/3)[x/k]^(1/3) (1st person's height)
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\n" ); document.write( "By what factor is the heavier person’s height greater than the
\n" ); document.write( "shorter person’s height?
\n" ); document.write( "Answer: 2^(1/3)
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\n" ); document.write( "Cheers,
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