document.write( "Question 424085: Height and Weight Suppose that the weight of a
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document.write( "person is directly proportional to the cube of the
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document.write( "person’s height. If one person weighs twice as much
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document.write( "as a (similarly proportioned) second person, by what
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document.write( "factor is the heavier person’s height greater than the
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document.write( "shorter person’s height?
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Algebra.Com's Answer #295725 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Height and Weight \n" ); document.write( "--------------------------------- \n" ); document.write( "Suppose that the weight of a \n" ); document.write( "person is directly proportional to the cube of the \n" ); document.write( "person’s height. \n" ); document.write( "-- \n" ); document.write( "W = k*H^3 \n" ); document.write( "---------------------------------------- \n" ); document.write( "If one person weighs twice as much \n" ); document.write( "as a (similarly proportioned) second person, by what \n" ); document.write( "factor is the heavier person’s height greater than the \n" ); document.write( "shorter person’s height? \n" ); document.write( "-- \n" ); document.write( "Let the 2nd person's weight be \"x\" \n" ); document.write( "x = k*H^3 \n" ); document.write( "H = [x/k]^(1/3) (2nd person's height) \n" ); document.write( "-------------------\r \n" ); document.write( "\n" ); document.write( "The 1st person's weight is \"2x\" \n" ); document.write( "2x = kH^3 \n" ); document.write( "H = [2x/k]^(1/3) \n" ); document.write( "H = 2^(1/3)[x/k]^(1/3) (1st person's height) \n" ); document.write( "----- \n" ); document.write( "By what factor is the heavier person’s height greater than the \n" ); document.write( "shorter person’s height? \n" ); document.write( "Answer: 2^(1/3) \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |