document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=424078>Question 424078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A trader bought some petrol for $500. He paid $x for each litre of petrol.<BR>\n" );
document.write( "a) Find in term of x, an expression for the number of litres he bought,<BR>\n" );
document.write( "b) Due to a leak, he lost 3 litres of petrol. He sold the remainder of the petrol for $1 per litre more than he paid for it. Write down an expression, in terms of x, for the sum of money he received,<BR>\n" );
document.write( "c) He made a profit of $20. i) Write down an equation in x to represent this information and show that it reduces to 3(x)^2 + 23 x -500 = 0. ii) Solve this equation, giving both your answers correct to one decimal place.<BR>\n" );
document.write( "d) Find, correct to the nearest whole number, how many litres of petrol he sold.\r<BR>\n" );
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document.write( "*I know it's a long question, but please try to understand I can't put the parts separately because then they wouldn't make sense. Please answer as soon as possible. Much appreciated :) =)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295722 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A trader bought some petrol for $500. He paid $x for each litre of petrol.<BR>\n" );
document.write( "a) Find in term of x, an expression for the number of litres he bought,\r<BR>\n" );
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document.write( "number of liters = 500/x\r<BR>\n" );
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document.write( "b) Due to a leak, he lost 3 litres of petrol. He sold the remainder of the petrol for $1 per litre more than he paid for it. Write down an expression, in terms of x, for the sum of money he received,\r<BR>\n" );
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document.write( "((500/x)-3 )(x+1) = money received.\r<BR>\n" );
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document.write( "c) He made a profit of $20. <BR>\n" );
document.write( "((500/x)-3 )(x+1)-500 =20<BR>\n" );
document.write( "(500-3x)/x*(x+1)-500=20<BR>\n" );
document.write( "multiply by x<BR>\n" );
document.write( "(500-3x)(x+1)-500x=20x<BR>\n" );
document.write( "500x+500-3x^2-3x-500x=20x<BR>\n" );
document.write( "500-3x^2-3x-20x=0<BR>\n" );
document.write( "-3x^2-23x+500=0<BR>\n" );
document.write( "/-1<BR>\n" );
document.write( "3x^2+23x-500=0<BR>\n" );
document.write( "i) Write down an equation in x to represent this information and show that it reduces to 3(x)^2 + 23 x -500 = 0. ii) Solve this equation, giving both your answers correct to one decimal place.<BR>\n" );
document.write( "Find the roots of the equation by quadratic formula\r<BR>\n" );
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document.write( "a=  3 , b =23   , c = -500    .\r<BR>\n" );
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document.write( "b^2-4ac= 6529\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29 ALIGN=MIDDLE  ALT=\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x1=%28-23%2Bsqrt%286529%29%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x1=%28-23%2Bsqrt%286529%29%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x1= 9.63<BR>\n" );
document.write( "Cost per litre =$ 9.6<BR>\n" );
document.write( " <BR>\n" );
document.write( "...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x2=%28-23-sqrt%286529%29%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x2=%28-23-sqrt%286529%29%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "This is negative. so ignore\r<BR>\n" );
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document.write( "d) Find, correct to the nearest whole number, how many litres of petrol he sold.\r<BR>\n" );
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document.write( "Each litre costs $9.6<BR>\n" );
document.write( "he paid total $500<BR>\n" );
document.write( "Number of litres = 500/9.6<BR>\n" );
document.write( "Number of litres bought = 52<BR>\n" );
document.write( "Number of litres sold 52-3 = 49<BR>\n" );
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