document.write( "Question 44695This question is from textbook beginning algebra
\n" ); document.write( ": 61) In Anna's purse there are 11 coins consisting of nickels and dimes.If the total value of these coins is $0.95,how many of each type of coin are there?\r
\n" ); document.write( "\n" ); document.write( "#61) A bank customer withdraws $200 from her account in $10 and $20 bills.she requests twice as many $20 as $10 bills.How many of each kind of bill does she receive?
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Algebra.Com's Answer #29571 by checkley71(8403)\"\" \"About 
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X+Y=11 & 5X+10Y=95 OR X=11-Y THUS 5(11-Y)+10Y=95 OR 55-5Y+10Y=95 OR 5Y=40 OR
\n" ); document.write( "Y=40/5 OR Y=8 THUS THERE ARE 8 DIMES FOR 80 CENTS THEN THERE ARE X+8=11 OR X=3 NICKELS FOR 15 CENTS FOR 80+15=95 OR 95=95.\r
\n" ); document.write( "\n" ); document.write( "10*X+20*2X=200 OR 10X+40X=200 OR 50X=200 OR X=200/50 OR X=4 TEN DOLLAR BILLS
\n" ); document.write( "THEN 2*4=8 20 DOLLAR BILLS
\n" ); document.write( "PROOF 4*10+8*20=200 OR 40+160=200 OR 200=200\r
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