document.write( "Question 423888: How many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? Show you process.\r
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Algebra.Com's Answer #295701 by dnanos(83)![]() ![]() You can put this solution on YOUR website! let x litters of the 14% solution. \n" ); document.write( "Then we obtain x+20 litters of the 30%. \n" ); document.write( "The pure alcohol litters before and after mixing must be equal. \n" ); document.write( "So we obtain an equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply by 100 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Divide by 16 \n" ); document.write( " \n" ); document.write( "x=25 \n" ); document.write( "So 25 litters 14% needed. \n" ); document.write( " |