document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44688>Question 44688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many four letter code words can be formed using a standard 26 letter alphabet if repetition is allowed?  and then if repetition is not allowed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29564 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Any of 26 letter can be in any of 4 spots, so there are 26^4 = 456,976 possibilities<BR>\n" );
document.write( "If there is no repeating, then the answer is less, because, even though 26 letters can be first, only 25 can be second, 24 can be third, and 23 can be last, so we get<BR>\n" );
document.write( "26 x 25 x 24 x 23 = 358,800 possibilities </SPAN>\n" );
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