document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=423971>Question 423971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve y=1/2x+4<BR>\n" );
document.write( "             2y+2x=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295624 by </B><A HREF=/tutors/aboutme.mpl?userid=linht117><B>linht117(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=linht117><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=1/2x+4<BR>\n" );
document.write( "2y+2x=2\r<BR>\n" );
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document.write( "use the substitution method, plug \"y\" in the for the second equation<BR>\n" );
document.write( "2(1/2x+4)+2x=2 simplify<BR>\n" );
document.write( "x+4+2x=2<BR>\n" );
document.write( "3x+4=2 subtract 4 from both sides<BR>\n" );
document.write( "3x=-2 divide by 3 from both sides<BR>\n" );
document.write( "x=-2/3\r<BR>\n" );
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document.write( "now plug (-2/3) into an original equation and solve<BR>\n" );
document.write( "y=1/2(-2/3)+4<BR>\n" );
document.write( "y=-1/3+4<BR>\n" );
document.write( "y=11/4 or 3.7 </SPAN>\n" );
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