document.write( "Question 423933: Solve this equation exactly for x (ok to leave in ln or log form).\r
\n" ); document.write( "\n" ); document.write( "log(x)+log(2x)=2
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Algebra.Com's Answer #295602 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
first some basic rules to remember:\r
\n" ); document.write( "\n" ); document.write( " Log Rules:\r
\n" ); document.write( "\n" ); document.write( " 1) \"logb%28mn%29+=+logb%28m%29+%2B+logb%28n%29\"\r
\n" ); document.write( "\n" ); document.write( " 2) \"logb%28m%2Fn%29+=+logb%28m%29+-+logb%28n%29\"\r
\n" ); document.write( "\n" ); document.write( " 3) \"logb%28mn%29+=+n%2Alogb%28m%29\"\r
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\n" ); document.write( "\n" ); document.write( "you have:\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%29%2Blog%282x%29=2\".....so, use the rule number 1\r
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\n" ); document.write( "\n" ); document.write( "\"log%28x%282x%29%29=2\".......I assume the base is \"10\"...By the definition of the logarithm implies\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%282x%29%29=10%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2=100\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=100%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2850%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%282%2A25%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=5sqrt%282%29\"\r
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