document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=423940>Question 423940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is six times its width. If the perimeter of the rectangle is 126 ft, find it area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295599 by </B><A HREF=/tutors/aboutme.mpl?userid=Gersid><B>Gersid(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gersid><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with:<BR>\n" );
document.write( "P = 2(L+W) Substitute P = 126, L = 6W<BR>\n" );
document.write( "126 = 2(6W+W) Simplify.<BR>\n" );
document.write( "63 = 7W Divide by 7.<BR>\n" );
document.write( "9 = W and L = 6(9) = 54.<BR>\n" );
document.write( "Area:<BR>\n" );
document.write( "A = L*W<BR>\n" );
document.write( "A = 54*9<BR>\n" );
document.write( "A = 486 sq.ft. </SPAN>\n" );
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