document.write( "Question 423910: PROBLEM:\r
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document.write( "The integer 48 is to be expressed as a sum of x consecutive odd integers. The value of x could be which of the following?\r
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document.write( " I. 2
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document.write( " II. 4
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document.write( "III. 6\r
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document.write( "a. I only
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document.write( "b. II only
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document.write( "c. I and II only
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document.write( "d. II and III only
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document.write( "e. I, II and III only\r
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document.write( "MY QUESTION:
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document.write( "**HOW DO I SOLVE THIS?** \n" );
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Algebra.Com's Answer #295585 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! consecutive odd integers are x, x+2, x+4, x+6, x+8, x+10 ....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I 2 . \n" ); document.write( " For 2 consecutive odd integers, the quotient of (48-2)/2 must be an odd integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "II 4\r \n" ); document.write( "\n" ); document.write( "(2 + 4 + 6 =12) \r \n" ); document.write( "\n" ); document.write( "For 4 consecutive odd integers, the quotient of (48 - 12)/4 must be an odd integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "III 6\r \n" ); document.write( "\n" ); document.write( "( 2+4+6+8+10= 30) \n" ); document.write( "for 6 consecutive odd integers, the quotient of (48-30)/6 must be an odd integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here all conditions are satisfied.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, answer is e.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |