document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=423890>Question 423890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2x+5)/5 = (3x+1)/2 + (-x+7)/2  Solve equation and check solution.  Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295581 by </B><A HREF=/tutors/aboutme.mpl?userid=linht117><B>linht117(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=linht117><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x+5)/5 = (3x+1)/2 + (-x+7)/2 rearrange equation<BR>\n" );
document.write( "10*(3x+1)/2 + 10*(-x+7)/2 = 10*(2x+5)/5 find LCD-10 and multiply it to each term <BR>\n" );
document.write( "10x+40=4x+10 solve for x<BR>\n" );
document.write( "x= -5<BR>\n" );
document.write( "______________________________<BR>\n" );
document.write( "plug -5 original equation<BR>\n" );
document.write( "[(2)(-5)]+5/5= [(3)(-5)]+1/2 + [(-(-5)+(7)]/2<BR>\n" );
document.write( "-10+5/5 = -15+1/2 + 5+7/2<BR>\n" );
document.write( "-5/5 = -14/2 + 12/2<BR>\n" );
document.write( "-1 = -7 + 6<BR>\n" );
document.write( "-1 = -1 </SPAN>\n" );
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