document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=423870>Question 423870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have always struggled with word problems and college word problems aren't any better, so could you please help me with these problems.\r<BR>\n" );
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document.write( "How much pure water must be mixed with 4 pints of 50% developer to produce a mixture that is 39% developer?\r<BR>\n" );
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document.write( "A researcher orders a broth of 8% glucose for her lab. However, she needs a stronger broth, one that is 14.1% glucose. Fortunately, she has 70.6 liters of 41% glucose broth in the stock room. How much 14.1% glucose broth can she make? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295550 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much pure water must be mixed with 4 pints of 50% developer to produce a mixture that is 39% developer?<BR>\n" );
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document.write( "How much pure water must be mixed with 4 pints of 50% developer to produce a mixture that is 39% developer?<BR>\n" );
document.write( "4 pts of 50% contain 2 pts of developer and 2 pts of water.<BR>\n" );
document.write( "If that 2 pts of developer is 39%,<BR>\n" );
document.write( "2 pt = 0.39S  (S = total solution)<BR>\n" );
document.write( "S = 2/0.39 =~ 5.128 pts<BR>\n" );
document.write( "5.128 - 4 = 1.128 pts of water to add<BR>\n" );
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document.write( "I'll do the other one later, or you can repost it.<BR>\n" );
document.write( "Posting more than one problem at a time usually results in waiting longer for help, btw.\r<BR>\n" );
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