document.write( "Question 423820: Please help me solve this word problem: It takes a freight train 2 hours more to travel 300 miles than it takes an express train to travel 280 miles. the rate of the express train is 20 miles per hour faster than the rate of the freight train. Find the rates of both trains. \r
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Algebra.Com's Answer #295532 by sudhanshu_kmr(1152)\"\" \"About 
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speed of freight train = x mph\r
\n" ); document.write( "\n" ); document.write( "speed of express train = x+20 mph\r
\n" ); document.write( "\n" ); document.write( "time taken by freight train for 300 miles = 300/x hrs\r
\n" ); document.write( "\n" ); document.write( "time taken by express train for 280 miles = 280/(x+20) hrs\r
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\n" ); document.write( "\n" ); document.write( "300/x = 280/(x+20) + 2\r
\n" ); document.write( "\n" ); document.write( "=> 300/x - 280/(x+20) = 2\r
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\n" ); document.write( "\n" ); document.write( "=> [ 300(x+20) -280x]/x(x+20) = 2\r
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\n" ); document.write( "\n" ); document.write( "=>[ 20x + 6000] = 2(x^2 +20x)\r
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\n" ); document.write( "\n" ); document.write( "=> 20x + 6000 = 2x^2 + 40x\r
\n" ); document.write( "\n" ); document.write( "=> 2x^2 + 20x - 6000 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x^2 + 10x - 3000 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x^2 + 60x - 50x - 3000 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x(x+60) -50(x +60)=0\r
\n" ); document.write( "\n" ); document.write( "=>(x-50)(x+60) = 0\r
\n" ); document.write( "\n" ); document.write( "now, x=50 mph because, x= -60 not possible.\r
\n" ); document.write( "\n" ); document.write( "so, speed of freight train = 50 mph\r
\n" ); document.write( "\n" ); document.write( "speed of express train = 70 mph\r
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\n" ); document.write( "\n" ); document.write( "if any doubt, please contact....
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