document.write( "Question 423814: The sum of two digits of a number is 11.\r
\n" ); document.write( "\n" ); document.write( "If the digits are reversed the number is 63 more than the original number.\r
\n" ); document.write( "\n" ); document.write( "What is the original number? \n" ); document.write( "
Algebra.Com's Answer #295526 by rfadrogane(214)\"\" \"About 
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The sum of two digits of a number is 11.
\n" ); document.write( "If the digits are reversed the number is 63 more than the original number.
\n" ); document.write( "What is the original number?
\n" ); document.write( "Let: N = the original number.
\n" ); document.write( "N = 10t+u
\n" ); document.write( "t=the ten's digit
\n" ); document.write( "u-unit digit\r
\n" ); document.write( "\n" ); document.write( "Sol'n:
\n" ); document.write( "t+u=11 ----(1), the sum of two digits of a number is 11.
\n" ); document.write( "10u+t=(10t+u)+63, when the digits are reversed the number is 63 more than the original number.
\n" ); document.write( "9t-9u=-63, when divide by 9
\n" ); document.write( "t-u = -7----(2)
\n" ); document.write( "Add (1) and (2).
\n" ); document.write( "2t=4
\n" ); document.write( "t=2 and for u:
\n" ); document.write( "u=11-2
\n" ); document.write( "u=9
\n" ); document.write( "thus,
\n" ); document.write( "N=10(2)+9
\n" ); document.write( "N=29 ----answer
\n" ); document.write( "Check:
\n" ); document.write( "92-29=63
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