document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44663>Question 44663</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh>Algebra and Trigonometry with Analytic geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> For the function defined by f(x)= 2-x^2, 0 less or equal than x, use a sketch to help find a formula for f^-1(x).  My answer is f^-2(x)= squrt2-x, x less or equal than 2.  This I'm not sure of.  Thanks as always for looking at my post. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29550 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the function defined by f(x)= 2-x^2, 0 less or equal than x, use a sketch to help find a formula for f^-1(x). My answer is f^-2(x)= squrt2-x, x less or equal than 2. \r<BR>\n" );
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document.write( "If you sketch f(x) you will have the right half of a parabola opening<BR>\n" );
document.write( "downward with its vertex at (0,2).\r<BR>\n" );
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document.write( "The inverse is x=2-y^2<BR>\n" );
document.write( "y^2=2-x<BR>\n" );
document.write( "y=sqrt(2-x) with x<=2\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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