document.write( "Question 423721: a lab needs to make 100 gallons of a 18% acid solution by mixing a 12% acid solution with 20% solution. How many gallons of each solution is needed? \n" ); document.write( "
Algebra.Com's Answer #295485 by mananth(16946) You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "12 ---------------- x \n" ); document.write( "20 ---------------- 100-x \n" ); document.write( "Total18.00%--------------100 ...... \n" ); document.write( "12x+20(100-x)=18*100 \n" ); document.write( "12x+2000 -20x=1800 \n" ); document.write( "12x-20x= 1800-2000 \n" ); document.write( "-8x=-200 \n" ); document.write( "/-8 \n" ); document.write( "x=25 liters of 12.00% \r \n" ); document.write( "\n" ); document.write( "75 liters of 20.00% \n" ); document.write( " \n" ); document.write( " |