document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=423734>Question 423734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the next steps of proving this equation: (3-3cos(x))(1+cos(x))= 3sin^2(x).\r<BR>\n" );
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document.write( "I have factored it out to be: -3cos^2(x) + 3= 3sin^2(x)...but I dont know if it is correct. Please help me :) Thank you!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295480 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3-3cos(x))(1+cos(x))= 3sin^2(x).<BR>\n" );
document.write( "..<BR>\n" );
document.write( "starting with left side.<BR>\n" );
document.write( "3(1-cosx)(1+cos)<BR>\n" );
document.write( "convert to difference of squares.<BR>\n" );
document.write( "=3(1-cos^2x)<BR>\n" );
document.write( "=3sin^2x<BR>\n" );
document.write( "verified: left side=right side </SPAN>\n" );
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