document.write( "Question 423681: Trains A and B are traveling in the same direction on parallel tracks. train A is traveling at 100 miles per hour and train B is traveling at 104 miles per hour. Train A passes a station at 6:10 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #295438 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Train A speed 100 mph \n" ); document.write( "Train B speed 104 mph \n" ); document.write( " \n" ); document.write( "Train A passes station at 06:10 \n" ); document.write( "Train B passes station at 06:40 \n" ); document.write( " \n" ); document.write( "Difference in time=00:30 \n" ); document.write( "Train A will have covered 50 miles before Train B starts \n" ); document.write( "catch up distance= 50 miles \n" ); document.write( "catch up speed = 104-100 mph \n" ); document.write( "catch up speed = 4 mph \n" ); document.write( " \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 50/4 \n" ); document.write( "catch up time= 12.5 hours \n" ); document.write( " \n" ); document.write( " |