document.write( "Question 44653: elimination method\r
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document.write( "2x/3 + 3y/4 =11/12
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document.write( "x/3 + 7y/18 =1/2\r
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document.write( "wouldn't 12 be the common denominator in the first equation
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document.write( "help \n" );
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Algebra.Com's Answer #29540 by adamchapman(301)![]() ![]() ![]() You can put this solution on YOUR website! You are right about 12 being the common denominator for the first equation. \n" ); document.write( "My working is shown below. Hopefully this example will help you in future questions of this type: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Rearrange to give y in terms of x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now the second part: \n" ); document.write( " \n" ); document.write( "Substituite equation (1) into equation (2) for y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Rearrange to give x: \n" ); document.write( " \n" ); document.write( "Rearrange to give x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute equation (3) into equation (1) to find y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the solution to the two original equations is x=10/9 and y=19/81.\r \n" ); document.write( "\n" ); document.write( "I hope this helps. \n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk \n" ); document.write( "Adam\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |