document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=423448>Question 423448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the linear system and check your solution algebraically. \r<BR>\n" );
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document.write( "{ 2x - 3y = 8<BR>\n" );
document.write( "   x - 2y = 2\r<BR>\n" );
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document.write( "***please i really need your help ASAP! thankyou so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295355 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply 2nd equation by -2 and add to 1st equation<BR>\n" );
document.write( "___ this will eliminate the x terms, because the coefficients will have the same number but different signs\r<BR>\n" );
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document.write( "[-2x + 4y] + [2x - 3y] = [-4] + [8]\r<BR>\n" );
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document.write( "y = 4\r<BR>\n" );
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document.write( "substitute the value of y into one of the equations to find x\r<BR>\n" );
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document.write( "x - 2(4) = 2\r<BR>\n" );
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document.write( "x = 10 </SPAN>\n" );
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