document.write( "Question 423430: do i take .80/0, .80/1, .80/2, .80/3, .80/4 to find my probabilty???? If i am in the wrong thought process please help set me straight. \r
\n" ); document.write( "\n" ); document.write( "First fill in this table (Round to 3 decimals)
\n" ); document.write( " BINOMIAL Probability Distribution
\n" ); document.write( "N=4 P=.80
\n" ); document.write( "Number of successes(x) probability
\n" ); document.write( "0 ?
\n" ); document.write( "1 ?
\n" ); document.write( "2 ?
\n" ); document.write( "3 ?
\n" ); document.write( "4 ?
\n" ); document.write( "2a) Mean= expected value for the # of sales= ____
\n" ); document.write( "Variance = _________\r
\n" ); document.write( "\n" ); document.write( "Use the table to answer the following questions:
\n" ); document.write( "2b) What is the probability that atleast1 policy is sold?
\n" ); document.write( "2c) What is the probability that the representative sells more than 1 policy?
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Algebra.Com's Answer #295342 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "Would recommend taking a look at the statistical problems posted on this site.
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document.write( "A 'WEALTH' of Information available to all who care to view the solutions 
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document.write( "done by Tutors on the subject.
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document.write( "re: BINOMIAL Probability Distribution
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx*  where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p =.8 and q = .2 and n = 4
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document.write( "nCx = 
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document.write( "P(0) = (.2)^4 = .0016
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document.write( "P(1) = 4(.8)^1(.2)^3 = 0.0256
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document.write( "P(2) = 6(.8)^2(.2)^2= 0.1536
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document.write( "P(3) = 4(.8)^3(.2)^1 = 0.4096
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document.write( "P(4) = (.8)^4 = 0.4096\r
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document.write( "Mean = np = 4*.8
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document.write( "Variance = npq = 4*.8*.2
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document.write( "P(at least one) = 1- P(0)
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document.write( "P(more than one) = 1 - P0) - P(1) \n" );
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