document.write( "Question 423339: -90(t) + 4.905 (t*t) -150 = 19.9! !! can u explain to me how they found t=19.9 ? \n" ); document.write( "
Algebra.Com's Answer #295288 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
if i understood your question correctly, you have a formula that is:\r
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\n" ); document.write( "\n" ); document.write( "4.905*t^2 - 90*t - 150 = 0\r
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\n" ); document.write( "\n" ); document.write( "you want to find the roots of this equation.\r
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\n" ); document.write( "\n" ); document.write( "you use the quadratic formula.\r
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\n" ); document.write( "\n" ); document.write( "this give you an answer of:\r
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\n" ); document.write( "\n" ); document.write( "x = 19.88641
\n" ); document.write( "or:
\n" ); document.write( "x = -1.53779\r
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\n" ); document.write( "\n" ); document.write( "round these to the nearest 10th and you get:\r
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\n" ); document.write( "\n" ); document.write( "x = 19.9
\n" ); document.write( "or:
\n" ); document.write( "x = -1.5\r
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\n" ); document.write( "\n" ); document.write( "the 19.9 looks like the number you are showing.\r
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\n" ); document.write( "\n" ); document.write( "from what i can see, it is one of the roots of the quadratic equation of:\r
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\n" ); document.write( "\n" ); document.write( "4.905*t^2 - 90*t - 150 = 0\r
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\n" ); document.write( "\n" ); document.write( "the standard form of a quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "ax^2 + bx + c = 0\r
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\n" ); document.write( "\n" ); document.write( "this makes:\r
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\n" ); document.write( "\n" ); document.write( "a = 4.905
\n" ); document.write( "b = -90
\n" ); document.write( "c = -150\r
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\n" ); document.write( "\n" ); document.write( "the quadratic formula give you:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "you solve by plugging in the values for a,b,c derived from above.\r
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\n" ); document.write( "\n" ); document.write( "the values of x = 19.9 and x = -1.5 are the roots of the quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "these are the value of x when the graph of the equation crosses the x-axis.\r
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\n" ); document.write( "\n" ); document.write( "the graph of your equation of y = 4.905*t^2 - 90*t - 150 looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C25%2C-800%2C800%2C4.905%2Ax%5E2+-+90%2Ax+-+150%29\"\r
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