document.write( "Question 422132: Solve for x.
\n" ); document.write( "log (base 2)[x^2 + 5] = log(base 2)6x \n" ); document.write( "
Algebra.Com's Answer #295279 by lwsshak3(11628)\"\" \"About 
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Solve for x.
\n" ); document.write( "log (base 2)[x^2 + 5] = log(base 2)6x
\n" ); document.write( "..
\n" ); document.write( "log2(x^2+5)=log2(6x)
\n" ); document.write( "log2(x^2+5)-log2(6x)=0
\n" ); document.write( "log2(x^2+5)/(6x)=0
\n" ); document.write( "convert to exponential form.
\n" ); document.write( "base raised to the logarithm of a number=number. In this case the base=2,the logarithm of the number=0, and the number=(x^2+5)/(6x)
\n" ); document.write( "2^0=(x^2+5)/(6x)=1
\n" ); document.write( "x^2+5=6x
\n" ); document.write( "x^2-6x+5=0
\n" ); document.write( "(x-5)(x-1)=0
\n" ); document.write( "x=5
\n" ); document.write( "x=1\r
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