document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44601>Question 44601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have sent this before and I've checked the solutions on the website on this topic but I still can't find the answers.  Perhaps, some of tutors can give me a hand.\r<BR>\n" );
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document.write( "Two towns P and Q are 35 km apart. Peter starts cycling from P towards Q at 12 p.m. at 20 km/h until he is 16 km from P, when he changes speed so that he arrives at Q at 2 p.m.  John leaves Q at 12:30 p.m. and cycles to P at a constant speed 26 km/h, find <BR>\n" );
document.write( "a)the time when Peter and John meet.<BR>\n" );
document.write( "b)the distance that they will meet\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29525 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE NUMBERS GIVEN IN THIS PROBLEM ALL LEAD TO FRACTIONS INVOLVING HRS,MTS AND SECS.ARE YOU SURE YOU GOT THE NUMBERS RIGHT?IS DISTANCE BETWEN P AND Q =34 KM OR 35 KM?<BR>\n" );
document.write( "Two towns P and Q are 35 km apart. Peter starts cycling from P towards Q at 12 p.m. at 20 km/h until he is 16 km from P, when he changes speed so that he arrives at Q at 2 p.m. John leaves Q at 12:30 p.m. and cycles to P at a constant speed 26 km/h, find<BR>\n" );
document.write( "a)the time when Peter and John meet.<BR>\n" );
document.write( "b)the distance that they will meet <BR>\n" );
document.write( "PETER TRAVELS STARTING FROM P AT 12=00 PM GOING AT 20 KMPH FOR 16 KM<BR>\n" );
document.write( "TIME TAKEN =16/20=0.8 HRS=0.8*60=48 MTS….THAT IS AT 12 =48<BR>\n" );
document.write( "BALANCE DISTANCE TO Q =35-16=19 KM.<BR>\n" );
document.write( "TIME TAKEN TO REACH =2=00 PM THAT IS 14=00 HRS<BR>\n" );
document.write( "TRAVEL TIME  IS 14=00 - 12 =48 =1 HR12 MTS. = 1 +12/60 HRS =6/5 HRS.<BR>\n" );
document.write( "PETERS SPEED DURING THIS TRAVEL =19/(6/5)=5*19/6=95/6 KMPH<BR>\n" );
document.write( "JOHN LEAVES Q AT 12=30 PM.<BR>\n" );
document.write( "TILL 12=48 HE TRAVELS FOR 12=48 -12=00=18 MTS=18/60 HRS =0.3 HRS.<BR>\n" );
document.write( "DISTANCE TRAVELLED BY JOHN DURING THIS PERIOD AT 26 KMPH=26*0.3=7.8 KM<BR>\n" );
document.write( "HENCE DISTANCE OF SEPERATION BETWEEN PETER AND JOHN AT 12 = 48 IS (35-16)-7.8=11.2 KM<BR>\n" );
document.write( "THEIR RELATIVE SPEED WHILE TRAVELLING IN OPPOSITE DIRECTIONS =95/6 +26=(95+156)/6=251/6 KMPH<BR>\n" );
document.write( "TIME TAKEN TO MEET =11.2/(251/6)=67.2/251 HRS = 16.06 MTS<BR>\n" );
document.write( "HENCE PETER AND JOHN MEET AT 12=48 + 16.06 MTS..THAT IS AT 13 HRS.04 MTS.36 SEC<BR>\n" );
document.write( "THE DISTANCE AT WHICH THEY MEET =16.06*95/6=4.24 KM THAT IS AT 16+4.24=18.24 KM FROM P. </SPAN>\n" );
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