document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422882>Question 422882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 44.  The second is three times the first and the third is 6 less than the first. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295073 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) x + y + z = 44<BR>\n" );
document.write( "2) y = 3x<BR>\n" );
document.write( "3) z = x - 6<BR>\n" );
document.write( "Substitute the value of y in 2) into equation 1):<BR>\n" );
document.write( "x + 3x + z = 44 -> 4x + z = 44<BR>\n" );
document.write( "Solve above equation for z in terms of x:<BR>\n" );
document.write( "z = 44 - 4x<BR>\n" );
document.write( "Substitute the above value for z into equation 3):<BR>\n" );
document.write( "44 - 4x = x - 6 -> 5x = 50 -> x = 10<BR>\n" );
document.write( "Therefore, from 2), y = 3*10 = 30<BR>\n" );
document.write( "And finally, from 3) z = 10 - 6 -> z = 4<BR>\n" );
document.write( "Ans: x=10,y=30,z=4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );