document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422823>Question 422823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please help me ? Triangle ABC: angle B is 5 times angle A and angle C is 18 degrees than 4 times angle A  Find the size of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295056 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First of all, we know the sum of all the angles in a triangle is 180 degrees:<BR>\n" );
document.write( "1) A + B + C = 180<BR>\n" );
document.write( "Since angle B is 5 times angle A we have:<BR>\n" );
document.write( "2) B = 5A<BR>\n" );
document.write( "And angle C is 18 (less or more? --not given in problem--assume more!) than 4 times angle A:<BR>\n" );
document.write( "3) C = 4A + 18<BR>\n" );
document.write( "We need to solve this system of equations.  <BR>\n" );
document.write( "Putting the value for B in 2) into 1) gives:<BR>\n" );
document.write( "A + 5A + C = 180 -> 6A + C = 180.<BR>\n" );
document.write( "Now solve for C and insert this value in equation 3):<BR>\n" );
document.write( "C = 180 - 6A -> 180 - 6A = 4A + 18<BR>\n" );
document.write( "Solve for A:<BR>\n" );
document.write( "10A = 162 or A = 16.2 deg.<BR>\n" );
document.write( "So B = 5*16.2 = 81 deg.<BR>\n" );
document.write( "Therefore C = 4*16.2 + 18 = 82.8 deg.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );