document.write( "Question 422756: find the trigonometric functions of alpha where the vertex of the parabola, y=X^2+8x-5, lies on its terminal side \n" ); document.write( "
Algebra.Com's Answer #295044 by Gogonati(855)\"\" \"About 
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Parabola with equation \"+y=X%5E2%2B8x-5\" has for vertex the point (-4,-21).
\n" ); document.write( "This point lies on the third quadrant and the slope of the line that pases on
\n" ); document.write( "(-4,-21) and (0,0) is: m= (0+21)/(0+4)=21/4. As we know the slope of the line is equal to the tangent of the angel that the line form with x-axis.\r
\n" ); document.write( "\n" ); document.write( " Tan(a)=21/4\r
\n" ); document.write( "\n" ); document.write( " (a)= arctan (21/4) ( (a) is the measure of the angle)\r
\n" ); document.write( "\n" ); document.write( " (a)= 80 degree.\r
\n" ); document.write( "\n" ); document.write( "Since the vertex of parabola is in the third quadrant the angel is 180+80=260 degree.
\n" ); document.write( " Tan(260)=5.67, Sin(260)=-0.98 and Cos(260) =-0.17
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