document.write( "Question 422805: The length of a rectangular room is 4 feet longer than twice the width. If the room's perimeter is 200 feet, what are the room's dimensions? \n" ); document.write( "
Algebra.Com's Answer #295038 by algebrahouse.com(1659)\"\" \"About 
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\"The length of a rectangular room is 4 feet longer than twice the width. If the room's perimeter is 200 feet, what are the room's dimensions?\"\r
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\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "2x + 4 = length {length is 4 longer than twice width}\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r
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\n" ); document.write( "\n" ); document.write( "2x + 2(2x + 4) = 200 {perimeter is 2(width) + 2(length)}
\n" ); document.write( "2x + 4x + 8 = 200 {used distributive property}
\n" ); document.write( "6x + 8 = 200 {combined like terms}
\n" ); document.write( "6x = 192 {subtracted 8 from both sides}
\n" ); document.write( "x = 32 {divided both sides by 6}
\n" ); document.write( "2x + 4 = 68 {substituted 32, in for x, into 2x + 4}\r
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\n" ); document.write( "\n" ); document.write( "width = 32ft and length = 68ft
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