document.write( "Question 422703: a rectangle has length (x-3)squared and width 4. the perimeter of the rectangle is 40. find the legth. \n" ); document.write( "
Algebra.Com's Answer #295026 by rfadrogane(214)\"\" \"About 
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a rectangle has length (x-3)squared and width 4. the perimeter of the rectangle is 40. find the length.
\n" ); document.write( "Sol'n:
\n" ); document.write( "P = 2w + 2L
\n" ); document.write( "L = x-3
\n" ); document.write( "W = 4
\n" ); document.write( "P = 40\r
\n" ); document.write( "\n" ); document.write( "40 = 2(4) + 2(x-3)
\n" ); document.write( "40-8 = 2x - 6
\n" ); document.write( "38 = 2x
\n" ); document.write( "x = 19
\n" ); document.write( "thus,
\n" ); document.write( "L = 19-3
\n" ); document.write( "L = 16 units ----answer\r
\n" ); document.write( "\n" ); document.write( "^_^ \n" ); document.write( "
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