document.write( "Question 422750: a box of chocolates has 45 pieces. If 9 pieces have nuts in them, what percentage are without nuts?
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Algebra.Com's Answer #295025 by rfadrogane(214)\"\" \"About 
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a box of chocolates has 45 pieces. If 9 pieces have nuts in them, what percentage are without nuts?
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\n" ); document.write( "% without nuts = {{45-9}/45}} x 100
\n" ); document.write( "% without nuts = 80% ----answer
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