document.write( "Question 422641: x^2+y^2-4x+6y+9=0 find the radius
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Algebra.Com's Answer #295021 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
x^2+y^2-4x+6y+9=0 find the radius\r
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\n" ); document.write( "\n" ); document.write( "Standard form for a circle:
\n" ); document.write( "(x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates of the center, and r=radius.\r
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\n" ); document.write( "x^2+y^2-4x+6y+9=0
\n" ); document.write( "completing the square,
\n" ); document.write( "(x^2-4x+4)+y^2+6y+9)=-9+4+9=4
\n" ); document.write( "(x-2)^2+(y+3)^2=4
\n" ); document.write( "This is a circle with center at (2,-3) with radius=sqrt(4)=2\r
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