document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422719>Question 422719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of linear equations. (If the system has no solution, enter NONE for each answer. If the system is dependent, enter INFINITELY MANY for each answer.)<BR>\n" );
document.write( "   x+5y=2<BR>\n" );
document.write( "  y=x+4\r<BR>\n" );
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document.write( "x =   ?<BR>\n" );
document.write( "y =  ?\r<BR>\n" );
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document.write( "Pls show me the steps on how to get the answer. thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #295010 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=295010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> step 1 put both the eq in the same form<BR>\n" );
document.write( "x+5y=2<BR>\n" );
document.write( "x-y=-4<BR>\n" );
document.write( "-------   we have several ways <BR>\n" );
document.write( "1. By substitution\r<BR>\n" );
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document.write( "x=2-5y from eq 1 and substitute in eq 2\r<BR>\n" );
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document.write( "2-5y-y=-4<BR>\n" );
document.write( "-6y=-6<BR>\n" );
document.write( "y=1<BR>\n" );
document.write( "x=2-5y=2-5=-3 </SPAN>\n" );
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