document.write( "Question 422583: Pat is 24 years older than his son Patrick. In 4 years Pat will be twice as old as Patrick. How old are they now?\r
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Algebra.Com's Answer #294988 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let s = son's present age \n" ); document.write( "let f = father's present age \n" ); document.write( ": \n" ); document.write( "Pat is 24 years older than his son Patrick. \n" ); document.write( "f = s + 24 \n" ); document.write( ": \n" ); document.write( "In 4 years Pat will be twice as old as Patrick. \n" ); document.write( "f + 4 = 2(s + 4) \n" ); document.write( "f + 4 = 2s + 8 \n" ); document.write( "f = 2s + 8 - 4 \n" ); document.write( "f = 2s + 4 \n" ); document.write( "replace f with (s+24) \n" ); document.write( "s + 24 = 2s + 4 \n" ); document.write( "24 - 4 = 2s - s \n" ); document.write( "s = 20 is the son's present age \n" ); document.write( "then \n" ); document.write( "20 + 24 = 44 yrs father's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check in four years father is 48 and son is 24.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |