document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422657>Question 422657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In trting to fins out how i can solve this linear system problem u-v= 0 and 7u+v=0 using substitution method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294987 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> u-v= 0 --> u = v<BR>\n" );
document.write( "7u+v=0<BR>\n" );
document.write( "7v+v = 0<BR>\n" );
document.write( "v = 0<BR>\n" );
document.write( "u = 0\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );