document.write( "Question 422285: can you help me with this ..
\n" ); document.write( "solve for x : log5(10x+4) - log5 2 = 1/2log5 49 + 2log5 4
\n" ); document.write( "ALL THE 5'S ARE ACTUALLY SMALL, i just didnt no how to do it on my keybored, thanks for the help! \n" ); document.write( "

Algebra.Com's Answer #294972 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
solve for x : log5(10x+4) - log5(2) = 1/2log5(49) + 2log5(4)
\n" ); document.write( ":
\n" ); document.write( "1/2 is the square root exponent, return the exponent to inside the radical
\n" ); document.write( " $\"log5%28%2810x%2B4%29%2F2%29+=+log5%28sqrt%2849%29%29+%2B+log5%284%5E2%29\"$
\n" ); document.write( "Which is
\n" ); document.write( "log5(5x+2) = log5(7) + log(16)
\n" ); document.write( ":
\n" ); document.write( "log5(5x+2) = log5(7*16)
\n" ); document.write( "log5(5x+2) = log5(112)
\n" ); document.write( ":
\n" ); document.write( "therefore, we can say:
\n" ); document.write( "5x + 2 = 112
\n" ); document.write( "5x = 112 - 2
\n" ); document.write( "5x = 110
\n" ); document.write( "x = $\"110%2F5\"$
\n" ); document.write( "x = 22
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "

\n" );