document.write( "Question 422594: A jogger ran 6 miles up a hill and 10 miles on level ground. He ran 2mph faster on level ground than on the hill. If the total trip lasted 4 hours, how fast did he run uphill? \n" ); document.write( "
Algebra.Com's Answer #294961 by ankor@dixie-net.com(22740)\"\" \"About 
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A jogger ran 6 miles up a hill and 10 miles on level ground.
\n" ); document.write( "He ran 2mph faster on level ground than on the hill.
\n" ); document.write( " If the total trip lasted 4 hours, how fast did he run uphill?
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\n" ); document.write( "Let s = speed run uphill
\n" ); document.write( "then
\n" ); document.write( "(s+2) = speed on level ground
\n" ); document.write( ":
\n" ); document.write( "write a time equation, time = dist/speed
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\n" ); document.write( "uphill time + level ground time = 4 hrs
\n" ); document.write( "\"6%2Fs\" + \"10%2F%28%28s%2B2%29%29\" = 4
\n" ); document.write( "multiply by s(s+2)
\n" ); document.write( "s(s+2)*\"6%2Fs\" + s(s+2)*\"10%2F%28%28s%2B2%29%29\" = 4s(s+2)
\n" ); document.write( ":
\n" ); document.write( "cancel the denominators
\n" ); document.write( "6(s+2) + 10x = 4s(s+2)
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\n" ); document.write( "6s + 12 + 10s = 4s^2 + 8s
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\n" ); document.write( "Combine on the right
\n" ); document.write( "0 = 4s^2 + 8s - 6s - 10s - 12
\n" ); document.write( ":
\n" ); document.write( "a quadratic equation
\n" ); document.write( "4s^2 - 8s - 12 = 0
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\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "s^2 - 2s - 3 = 0
\n" ); document.write( "factor to
\n" ); document.write( "(s - 3)(s + 1) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "s = 3 mph up hill
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\n" ); document.write( "Check this by finding the actual time of each (5 mph is speed on level ground)
\n" ); document.write( "6/3 + 10/5 = 4
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