document.write( "Question 422594: A jogger ran 6 miles up a hill and 10 miles on level ground. He ran 2mph faster on level ground than on the hill. If the total trip lasted 4 hours, how fast did he run uphill? \n" ); document.write( "
Algebra.Com's Answer #294961 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A jogger ran 6 miles up a hill and 10 miles on level ground. \n" ); document.write( "He ran 2mph faster on level ground than on the hill. \n" ); document.write( " If the total trip lasted 4 hours, how fast did he run uphill? \n" ); document.write( ": \n" ); document.write( "Let s = speed run uphill \n" ); document.write( "then \n" ); document.write( "(s+2) = speed on level ground \n" ); document.write( ": \n" ); document.write( "write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "uphill time + level ground time = 4 hrs \n" ); document.write( " \n" ); document.write( "multiply by s(s+2) \n" ); document.write( "s(s+2)* \n" ); document.write( ": \n" ); document.write( "cancel the denominators \n" ); document.write( "6(s+2) + 10x = 4s(s+2) \n" ); document.write( ": \n" ); document.write( "6s + 12 + 10s = 4s^2 + 8s \n" ); document.write( ": \n" ); document.write( "Combine on the right \n" ); document.write( "0 = 4s^2 + 8s - 6s - 10s - 12 \n" ); document.write( ": \n" ); document.write( "a quadratic equation \n" ); document.write( "4s^2 - 8s - 12 = 0 \n" ); document.write( ": \n" ); document.write( "Simplify, divide by 4 \n" ); document.write( "s^2 - 2s - 3 = 0 \n" ); document.write( "factor to \n" ); document.write( "(s - 3)(s + 1) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "s = 3 mph up hill \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the actual time of each (5 mph is speed on level ground) \n" ); document.write( "6/3 + 10/5 = 4 \n" ); document.write( " \n" ); document.write( " |