document.write( "Question 422513: I am working on equation of a line in slope-intercept form. One example I don't get is (10,7) are my points and 3/8 is what I am seeing. So it's y-(7)=3/8(x-(10)) then y-7=3\8x-15/4 then y=3/8x-15/4+28/4 then y= 3/8x+13/4 so my question is where does the 15/4 and the 28/4 come from?  Thanks! \n" ); document.write( "
Algebra.Com's Answer #294931 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
you are given one point (10,7) and a slope \"3%2F8\"; you need to find equation of a line that goes through given point and has a given slope\r
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\n" ); document.write( "\n" ); document.write( "So it's \r
\n" ); document.write( "\n" ); document.write( "\"y-%287%29=3%2F8%28x-%2810%29%29\" then \r
\n" ); document.write( "\n" ); document.write( "\"y-7=%283%2F8%29x-%283%2F8%29%2810%29%29\".........reduce \"%283%2Fcross%288%294%29%28cross%2810%295%29%29=3%2A5%2F4=15%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"y-7=%283%2F8%29x-15%2F4%29\"..move \"-7\" to the right\r
\n" ); document.write( "\n" ); document.write( "\"y=%283%2F8%29x-15%2F4%2B+7%29\".....write \"7\" as a fraction with denominator \"4\" so you can subtract \"-15%2F4\" from it.....\"7%2A4%2F4=28%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%283%2F8%29x-15%2F4%2B+28%2F4%29\"...or\r
\n" ); document.write( "\n" ); document.write( "\"y=%283%2F8%29x%2B+%2828%2F4+-15%2F4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%283%2F8%29x%2B+%2828+-15%29%2F4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2F8%29x%2B+13%2F4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%283%2F8%29x%2B%2813%2F4%29%29%29+\" \r
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