document.write( "Question 422497: the diagnol of a rectangle is eighteen inches more than its width. The length of the rectangle is seventeen more than its width.what are the demensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #294926 by checkley79(3341)\"\" \"About 
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w^2+(w+17)^2=(w+18)^2
\n" ); document.write( "w^2+w^2+34w+289=w^2+36w+324
\n" ); document.write( "2w^2-w^2+34w-36w+289-324=0
\n" ); document.write( "w^2-2w-35=0
\n" ); document.write( "(w-7)(w+5)=0
\n" ); document.write( "w-7=0
\n" ); document.write( "w=7 ans. for the wwidth.
\n" ); document.write( "Proof:
\n" ); document.write( "7^2+(7+17)^2=(7+18)^2
\n" ); document.write( "49+24^2=25^2
\n" ); document.write( "49+576=625
\n" ); document.write( "625=625
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