document.write( "Question 422497: the diagnol of a rectangle is eighteen inches more than its width. The length of the rectangle is seventeen more than its width.what are the demensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #294926 by checkley79(3341) ![]() You can put this solution on YOUR website! w^2+(w+17)^2=(w+18)^2 \n" ); document.write( "w^2+w^2+34w+289=w^2+36w+324 \n" ); document.write( "2w^2-w^2+34w-36w+289-324=0 \n" ); document.write( "w^2-2w-35=0 \n" ); document.write( "(w-7)(w+5)=0 \n" ); document.write( "w-7=0 \n" ); document.write( "w=7 ans. for the wwidth. \n" ); document.write( "Proof: \n" ); document.write( "7^2+(7+17)^2=(7+18)^2 \n" ); document.write( "49+24^2=25^2 \n" ); document.write( "49+576=625 \n" ); document.write( "625=625 \n" ); document.write( " \n" ); document.write( " |