document.write( "Question 422480: the area of a square photograph is 300 square inches. to the nearest hundredth inch, what is the perimeter of the photograph? \n" ); document.write( "
Algebra.Com's Answer #294906 by duckness73(47)\"\" \"About 
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Let x = length of one side of the square photograph. Since you are looking for the perimeter, you are looking for the distance around the square; and since all of the sides of a square are of equal length, you have:\r
\n" ); document.write( "\n" ); document.write( "Perimeter = x + x + x + x = 4x.\r
\n" ); document.write( "\n" ); document.write( "The area of any rectangle is length * width. In your case, since the length and width are equal, \"Area+=+x%5E2\". We know from the problem that Area = 300, so we have:\r
\n" ); document.write( "\n" ); document.write( "\"Area+=+x%5E2+=+300\"
\n" ); document.write( "\"x+=+sqrt%28300%29\" (Taking the square root of both sides)
\n" ); document.write( "\"x+=+sqrt%28100+%2A+3%29+=+10+%2A+sqrt%283%29\" (simplifying the expression)\r
\n" ); document.write( "\n" ); document.write( "The perimeter = \"4+%2A+10+%2A+sqrt%283%29\" = \"40+%2A+sqrt%283%29\" = \"40+%2A+1.732\" = 69.28\r
\n" ); document.write( "\n" ); document.write( "Therefore the perimeter of the square photograph is 69.28 inches.
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