document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44596>Question 44596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second side of a triangle is 1 centimeter more than three times the first side. The third side is 2 centimeters longer than the second side. If the perimeter is 46 centimeters, find the lengh of each side of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29485 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second side of a triangle is 1 centimeter more than three times the first side. The third side is 2 centimeters longer than the second side. If the perimeter is 46 centimeters, find the lengh of each side of the triangle.<BR>\n" );
document.write( "First Side: s<BR>\n" );
document.write( "Second Side: 3s + 1<BR>\n" );
document.write( "Third Side: 3s + 1 + 2 = 3s + 3<BR>\n" );
document.write( "(s) + (3s + 1) + (3s + 3) = 46<BR>\n" );
document.write( "s + 3s + 1 + 3s + 3 = 46<BR>\n" );
document.write( "7s = 42<BR>\n" );
document.write( "s = 6<BR>\n" );
document.write( "First Side: s = 6<BR>\n" );
document.write( "Second Side: 3s + 1 = 3(6) + 1 = 19<BR>\n" );
document.write( "Third Side: 3s + 1 + 2 = 3s + 3 = 3(6) + 3 = 21<BR>\n" );
document.write( "6 x 19 x 21 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );