document.write( "Question 422167: x^2+x+(√x^2+x)-2=0\r
\n" ); document.write( "\n" ); document.write( "I'm thinking this can be re-written as 2x^2+(√2x^2)-2=0 but I'm completely confused in all of this. At some point, don't I need to balance the right and the left side of the equation?
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Algebra.Com's Answer #294811 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
No, you can't do that, this is a toughie
\n" ); document.write( "\"x%5E2%2Bx%2B%28sqrt%28x%5E2%2Bx%29%29-+2+=+0\"
\n" ); document.write( ":
\n" ); document.write( "\"x%5E2+%2B+x-+2\" = -\"sqrt%28x%5E2%2Bx%29\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"%28x%5E2+%2B+x-+2%29%5E2\" = \"x%5E2+%2B+x\"
\n" ); document.write( "FOIL the left
\n" ); document.write( "\"x%5E4%2B2x%5E3-3x%5E2-4x%2B4\" = \"x%5E2+%2B+x\"
\n" ); document.write( "combine on the left
\n" ); document.write( "\"x%5E4%2B2x%5E3-3x%5E2-x%5E2-4x-x%2B4\" = 0
\n" ); document.write( "\"x%5E4%2B2x%5E3-4x%5E2-5x%2B4\" = 0
\n" ); document.write( "What can you do with this? it won't factor, graph the original and the above equation, see what we have
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\n" ); document.write( "find the x intercepts, -1.6, and + .62 (not exact) Correction!!
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\n" ); document.write( "Check both values in the original equation, see if it works\r
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