document.write( "Question 422335: find the center of this ellipse: 16x^2+4y^2+64x+24y+36=0 \n" ); document.write( "
Algebra.Com's Answer #294804 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( " Standard Form of an Equation of an Ellipse is \"%28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+\"
\n" ); document.write( "where Pt(h,k) is the center and a and b are the respective vertices, distances from center.\r
\n" ); document.write( "\n" ); document.write( "Finding the center of the following ellipse:
\n" ); document.write( "16x^2+4y^2+64x+24y+36=0
\n" ); document.write( " 16(x^2 + 4x) + 4(y^2+6y)+36 = 0 |completing the squares
\n" ); document.write( " 16[(x+2)^2 -4] + 4[(y+3)^2-9] + 36 = 0
\n" ); document.write( " 16(x+2)^2 - 64 + 4(y+3)^2 - 36 + 36 = 0
\n" ); document.write( " 16(x+2)^2 + 4(y+3)^2 = 64
\n" ); document.write( " \"%28x%2B2%29%5E2%2F4+%2B+%28y%2B3%29%5E2%2F16+=+1\"
\n" ); document.write( "center pt(-2,-3)
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