document.write( "Question 422304: I need some help with a word problem that I need to translate to an algebraic problem and solve\r
\n" ); document.write( "\n" ); document.write( "Jackie either drives or bicycles from home to school. Her average speed when driving is 36mph, and her average speed when bicycling is 12mph. If it takes her 1/2 hour less to drive to school, how long does take her to go to school, and how far is the school from her home?
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Algebra.Com's Answer #294799 by ankor@dixie-net.com(22740)\"\" \"About 
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Jackie either drives or bicycles from home to school.
\n" ); document.write( " Her average speed when driving is 36mph, and her average speed when bicycling is 12mph.
\n" ); document.write( " If it takes her 1/2 hour less to drive to school, how long does take her to go
\n" ); document.write( " to school, and how far is the school from her home?
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\n" ); document.write( "Let d = distance from home to school
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\n" ); document.write( "Write a time equation; Time = dist/speed
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\n" ); document.write( "Bike time - drive time = .5 hrs
\n" ); document.write( "\"d%2F12\" - \"d%2F36\" = .5
\n" ); document.write( "multiply by 36 to clear the denominators
\n" ); document.write( "36*\"d%2F12\" - 36*\"d%2F36\" = 36(.5)
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "3d - d = 18
\n" ); document.write( "2d = 18
\n" ); document.write( "d = 9 mi is the distance
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\n" ); document.write( "How long?
\n" ); document.write( "9/12 = 3/4 hr to bike
\n" ); document.write( "9/36 = 1/4 hr to drive
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\n" ); document.write( "differ: 1/2 hr
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