document.write( "Question 422304: I need some help with a word problem that I need to translate to an algebraic problem and solve\r
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document.write( "Jackie either drives or bicycles from home to school. Her average speed when driving is 36mph, and her average speed when bicycling is 12mph. If it takes her 1/2 hour less to drive to school, how long does take her to go to school, and how far is the school from her home? \n" );
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Algebra.Com's Answer #294799 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Jackie either drives or bicycles from home to school. \n" ); document.write( " Her average speed when driving is 36mph, and her average speed when bicycling is 12mph. \n" ); document.write( " If it takes her 1/2 hour less to drive to school, how long does take her to go \n" ); document.write( " to school, and how far is the school from her home? \n" ); document.write( ": \n" ); document.write( "Let d = distance from home to school \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Bike time - drive time = .5 hrs \n" ); document.write( " \n" ); document.write( "multiply by 36 to clear the denominators \n" ); document.write( "36* \n" ); document.write( "Cancel the denominators \n" ); document.write( "3d - d = 18 \n" ); document.write( "2d = 18 \n" ); document.write( "d = 9 mi is the distance \n" ); document.write( "; \n" ); document.write( "How long? \n" ); document.write( "9/12 = 3/4 hr to bike \n" ); document.write( "9/36 = 1/4 hr to drive \n" ); document.write( "------------------------- \n" ); document.write( "differ: 1/2 hr \n" ); document.write( " |