document.write( "Question 422330: A father is now three times as old as his son. Twelve years ago he was six times as old as his son. Find the Present age of each \n" ); document.write( "
Algebra.Com's Answer #294794 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "A father is now three times as old as his son
\n" ); document.write( "Let x and 3x represent the ages of the son and father NOW repectively
\n" ); document.write( "Question states*** 12years ago...
\n" ); document.write( " 3x-12 = 6(x-12)
\n" ); document.write( "Solving for x
\n" ); document.write( " 3x-12 = 6x - 72
\n" ); document.write( " 60 = 3x
\n" ); document.write( " 20 = x, son's age now. The father is now 60.\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***12years ago...
\n" ); document.write( " 48 = 6*8 \n" ); document.write( "
\n" );