document.write( "Question 422330: A father is now three times as old as his son. Twelve years ago he was six times as old as his son. Find the Present age of each \n" ); document.write( "
Algebra.Com's Answer #294793 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"A father is now three times as old as his son. Twelve years ago he was six times as old as his son. Find the Present age of each\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = son's age now \n" ); document.write( "3x = father's age now {father is 3 times as old as his son}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 12 = son's age twelve years ago \n" ); document.write( "3x - 12 = father's age twelve years ago\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x - 12 = 6(x - 12) {twelve years ago, father was six times as old as his son} \n" ); document.write( "3x - 12 = 6x - 72 {used distributive property} \n" ); document.write( "3x = 6x - 60 {added 12 to both sides} \n" ); document.write( "-3x = -60 {subtracted 6x from both sides} \n" ); document.write( "x = 20 {divided both sides by -3} \n" ); document.write( "3x = 60 {substituted 20, in for x, into 3x}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "son is 20 now \n" ); document.write( "father is 60 now \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |