document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422322>Question 422322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/2 log base 2 (4) - 1/2 log base 2 (x) = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294785 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294785\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:\r<BR>\n" );
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document.write( "   3/2logbase 2 (4)-1/2logbase 2 (x)= 3\r<BR>\n" );
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document.write( "    log base 2 (4)^3/2- log base 2 (x)^1/2= 3\r<BR>\n" );
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document.write( "     log base2 (2)^3- log base2 (x)^1/2= log base2 (8)\r<BR>\n" );
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document.write( "  Subtract log base 2 (8) from both sides of equation.\r<BR>\n" );
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document.write( "     -log base 2 (x)^1/2= 0\r<BR>\n" );
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document.write( "      x^1/2 = 1 (Because log base 2 (1)= 0)\r<BR>\n" );
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document.write( "      x=1 </SPAN>\n" );
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