document.write( "Question 422003: What is the vertex and line of symmetry of f(x)=1/5x^2? I can figure out the graph but the fraction throws me off for the other. \n" ); document.write( "
Algebra.Com's Answer #294781 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "f(x)=1/5x^2 Vertex(0,0) Line of symmentry the y a-xis (or x = 0)\r
\n" ); document.write( "\n" ); document.write( "Note the Coefficient determines 2 things:
\n" ); document.write( "1) whether the parabola opens upward (>0 or downward(<0)
\n" ); document.write( "2) the broadness of the parabola
\n" ); document.write( "It has NO effect of the axis of symmetry.
\n" ); document.write( "Note: blue graph is: y = -5x^2
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