document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422293>Question 422293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can i know how about this question:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log+5%5E%283x-1%29+=+log+6%5E%28x%2B4%29+ ALIGN=MIDDLE  ALT=\"+log+5%5E%283x-1%29+=+log+6%5E%28x%2B4%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I try many way but I can't balance it >< </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294778 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log%28%285%5E%283x-1%29%29%29+=+log%28%28+6%5E%28x%2B4%29%29%29+ ALIGN=MIDDLE  ALT=\"+log%28%285%5E%283x-1%29%29%29+=+log%28%28+6%5E%28x%2B4%29%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "We start by using a property of logarithms, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29 ALIGN=MIDDLE  ALT=\"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to move the exponents of the arguments out in front:<BR>\n" );
document.write( "(3x-1)log(5) = (x+4)log(6)<BR>\n" );
document.write( "This gets the variable out of the exponents. We can now solve for x. First we simplify. Using the Distributive Property we get:<BR>\n" );
document.write( "(3x)log(5) - log(5) = (x)log(6) + 4log(6)<BR>\n" );
document.write( "Next we gather the x terms on one side and the other terms on the other side of the equation. Subtracting (x)log(6) and adding log(5) we get:<BR>\n" );
document.write( "(3x)log(5) (x)log(6) =  4log(6) +  log(5)<BR>\n" );
document.write( "Factoring out x on the left side we get:<BR>\n" );
document.write( "x(3log(5) - log(6)) =  4log(6) +  log(5)<BR>\n" );
document.write( "And then we divide by (3log(5) - log(6)):<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=++%284log%28%286%29%29+%2B++log%28%285%29%29%29%2F%283log%28%285%29%29+-+log%28%286%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "This is the solution to your equation.<br><BR>\n" );
document.write( "P.S. If your equation was<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%285%2C+%283x-1%29%29+=+log%286%2C+%28x%2B4%29%29 ALIGN=MIDDLE  ALT=\"log%285%2C+%283x-1%29%29+=+log%286%2C+%28x%2B4%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "instead of<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log%28%285%5E%283x-1%29%29%29+=+log%28%28+6%5E%28x%2B4%29%29%29+ ALIGN=MIDDLE  ALT=\"+log%28%285%5E%283x-1%29%29%29+=+log%28%28+6%5E%28x%2B4%29%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "then...<ul><li>The 5 and the 6 are the bases of the logarithms, not bases with exponents of 3x-1 and x=4.</li><li>The 3x-1 and x+4 are not exponents at all. They are the arguments of the logarithms.</li><li>Since you already know some of Algebra.com's formula syntax, use log(b, (a)) (with \"b\" being the base and \"a\" being the argument) to express logarithms of bases other than 10 or e. (Click on the \"Show source\" link just above this solution to see how I typed these logs.)</li></ul> </SPAN>\n" );
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